Algebra Lesson 1.5: Solving Equations with Parentheses

Practice Exercises:

In the following exercises, use the distributive property to get rid of the parentheses. Then solve for \(x\).

     1. 4(x+3) = 20
     2. 0=3(x-7)
     3. 2(3x-3)=12

Solutions video:

Another Practice Problem:

In the following exercise, use the distributive property to get rid of the parentheses on both sides. Then solve for \(x\).

     4. 4(3x-3)+1=2-4(x+3)

Solution video:

Here are some more challenging problems involving fractions:

     5. \(\frac{1}{3}(5y-2)+2y=y-\frac{1}{3}(2+3y)\)
     6. \( -\frac{1}{7}(2z-2)=\frac{3}{7}(6-z)\)
     7. \( 5(\frac{1}{10}t-2)=3(t+1)-\frac{1}{2}t\)